What is the correct order of operations for one-time pad cipher when using subtraction and mod 10 arithmetic?

What would be the proper order of operations for OTP encryption/decryption when using subtraction and mod 10? E.g. P - K = C or K - P = C

Most of the sources I have seen do not cover this topic or I didn't grasp the principles behind this encryption well enough. From what I gather it shouldn't matter as long as the pad key numbers (K) are truly random.

For instance:

PLAINCODE:  65417
OTP PAD(-): 47757
-----------------
CIPHER:     28760 

EDIT: From some tests I see that. When used for encryption, whether P + K or K + P to decrypt the original message you need to do C - K, otherwise K - C will not return P. When used for encryption, P - K since C + K will return P, otherwise K + C will not return the original plaincode.

Can someone please explain whether using subtraction or addition for encryption one has a security advantage over the other.

I advocate for $K-P\to C$ and $K-C\to P$ so that encryption and decryption are identical, as in the binary OTP. Each digit is processed modulo 10.

    OTP PAD K:  47757            OTP PAD K:  47757
  - PLAINTEXT:  65417          - CIPHERTEXT: 82340 
    -----------------            -----------------
  = CIPHERTEXT: 82340          = PLAINTEXT:  65417

Update: from functionality and security perspectives, $P-K\to C$ and $C+K\to P$ is perfectly fine; as well as $P+K\to C$ and $C-K\to P$. What I advocate has a single benefit: the same method/code is used for encryption and decryption.

The reason these three variants allow decryption and are perfectly secure is the same: the set $\{0,1,2,3,4,5,6,7,8,9\}$ is a group under addition modulo $10$ (if the group is not commutative, we need to change $K-C\to P$ into $(-C)+K\to P$ ). Therefore, there is nothing to learn about $P$ from $C$ when not knowing $K$.