A standard theorem is that boolean circuit satisfiability is NP-complete (shown in CLRS, for example).
I am interested in what these statements formally mean.
From CLRS, I can cite that
$$\text{CIRCUIT-SAT} = \{C \mid \text{$C$ is a satisfiable boolean combinational circuit}\}$$
In Bitansky et al., boolean circuit satisfiability is used to capture the statement to be proved.
However, this is not CIRCUIT-SAT: Bitansky et al. consider the satisfiability of a circuit $C$ for an input $x$. CIRCUIT-SAT merely describes the satisfiability of a circuit $C$ for any input $x$.
A zk-SNARK proves statements $x \in L$ for $L \in NP$.
What is done to create a zk-SNARK for boolean circuit satisfiability is to reduce $L$ to a boolean circuit $C$ such that $C$ is satisfiable for an input $x$ iff $x \in L$. $C$ models $L$, so to speak.
I am confused by people saying that boolean (or arithmetic) circuit satisfiability is NP-complete. As I understand it, $L$ needs to be modeled by a circuit $C$. However, if I went by the definition of CIRCUIT-SAT, $x$ would need to be converted to a circuit $C$.
What CIRCUIT-SAT for zk-SNARKs should look like is
$$\text{CIRCUIT-SAT} = \{ (C, x) \mid \text{$C$ is a satisfiable boolean combinational circuit for input $x$}\}$$
We want a circuit per language, not per input.
So, when someone says that satisfiability of circuits, R1CS, QSPs, or QAPs is NP-complete in the context of zk-SNARKs, are they in fact referring to my definition of CIRCUIT-SAT and similar ones?