Score:2

Hidden field equations - existence of zeroes

in flag

Let $\mathbb{F}_q$ be a finite field of size $q$ (prime), and $\mathbb{F}_{q^n}$ be a degree-$n$ algebraic extension of $\mathbb{F}_q$.

Let $F$ be a polynomial function $\mathbb{F}_{q^n} \to \mathbb{F}_{q^n}$ of the form $$ \sum_{i, j \in I_A} A_{i,j} X^{q^i + q^j} + \sum_{i\in I_B} B_i X^{q^i} + C $$ where $A_{i,j}, B_i,$ and $C$ are some constants in $\mathbb{F}_{q^n}$.

Given a random $D \in \mathbb{F}_{q^n}$, we need to find a solution $X$ for $F(X) = D$.

My question is: why does such a solution exist? Does the range of $F$ cover $\mathbb{F}_\mathbb{q^n}$? How do we check?

Score:0
ru flag

Such a solution does not necessarily exist unless $F(X)$ is a permutation polynomial over $\mathbb F_{q^n}$.

Permutation polynomials are precisely those whose range covers the whole field.

The paper Recognising permutation functions in polynomial time (by Neeraj Kayal, one of the authors of the AKS polynomial time primality test) gives a polynomial time test.

kelalaka avatar
in flag
Even, it is a permutation polynomial ( there is no simple kernel of $F$ that I can see) the question is not totally unanswered; how to find the solution.
Daniel S avatar
ru flag
The questioner did not ask how to find the unique solution, but as with all finite fields it can be found by taking a GCD with $X^{q^n}-X$.
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