We use DES in cipher feedback mode (CFB) to encrypt a plaintext $m = m_1\mathbin\|m_2\mathbin\|\ldots\mathbin\|m_{100}$ into a ciphertext $c_1\mathbin\|c_2\mathbin\|\ldots\mathbin\|c_{100}$, where each $m_i$ is 8-bit long. The ciphertext is sent to Bob. If $c_{15}$ and $c_{25}$ are missing and $c_8$ and $c_{88}$ are received as $c_8'$ and $c_{88}'$ wrongly, what $m_i$s can B compute correctly from the received ciphertext?
A transmission error in $c_i$ affects correctness of $m_i$ and
the next $n/s$ plaintext blocks.
n means the plaintext. ||=||=-bits
I am not sure
$c_8'$ transmission error affects $8$ to $20$, $c_{88}'$ transmission error affects $88$ to $100$.
$c_{15}$ and $c_{25}$ are missing. Therefore, $100 - 26 - 2 = 72$ can B compute correctly from the received ciphertext.
I was wonder if trasmission error caused error from the current ciphertext $_c8'$ to the next $[100/8]=13$ plaintext which is 20.
$c_{88}'$ transmission error affects $88$ to $100$.
if $c_{15}$ and $c_{25}$ are missing, how to compute it? Are they regarded as 2 error and 100 - 13- 13 - 2= 72 or regarded 2 missing text as shifting the entire text after c16?
Thank you so much!