Are asymmetric encryption and decryption same function?

In asymmetric key encryption, we have 2 functions, encrypt(m,k) and decrypt(m,k), and 2 keys, public_key and private_key.

And it must hold true that decrypt(encrypt(msg, public_key), private_key)) = msg.

Question 1: Are the encrypt(m,k) and decrypt(m,k) functions different, or are they the same function?

Question 2: Must it also hold true that encrypt(decrypt(msg, private_key), public_key)) = msg?

In asymmetric key encryption, we have 2 functions, encrypt(m,k) and decrypt(m,k), and 2 keys, public_key and private_key.

Well, if we dig down to the next level, we see that this is not quite true.

encrypt(m,k) is never a function, that is, is determanistic. If it were, then someone with a ciphertext $c$, the public key $k$ could verify if it corresponded to a guess $m'$ by simply checking if $\text{encrypt}(m', k) = c$

Because we want public key encryption to be secure even if we encrypt low entropy plaintexts (that is, ones that could be guessed), we always make the encryption function nondeterministic; that is, it can generate a large number of ciphertexts corresponding to a specific plaintext, key; this prevents the above attack.

If we were to express this in function notation, we have $c = \text{encrypt}(m,k,r)$ (where $r$ is a random value that changes what $c$ is, but not what it decrypts to).

Because public key decryption has no such security requirements, it doesn't take such a random input.

Given that fuller explination of how public key encryption works in practice, I believe that it should be easy to deduce answers to the two questions you asked.