Overriding Drupal.ajax.prototype is not working

KrzysiekK

9/2/23, 1:58 PM

I am trying to override Drupal.ajax.prototype.beforeSend like this:

(function($) {
  // In mymodule.js, which appears after ajax.js in the page build
  Drupal.ajax.prototype.beforeSend = function(xmlhttprequest, options) {
    console.log('overridden!')
  }
})(jQuery);

The file that contains the code is listed below core's ajax.js in the page's source, yet it's the console.log I put inside core's ajax.js beforeSend that is showing up.

What else is to it? Has anything been changed in Drupal? Using version 9.3. Can't override any of those functions.

0 + 0

javascript

ajax

Kevin

9/2/23, 2:15 PM

Did you also pass in the 'Drupal' object?

KrzysiekK

9/2/23, 2:17 PM

I even passed 'jQuery, Drupal, drupalSettings'.

4uk4

9/2/23, 2:19 PM

Isn't `ajax` spelled `Ajax`?

KrzysiekK

9/2/23, 2:22 PM

Wow, actually there are both "ajaxes", and the one I need is, indeed, spelled 'Ajax'. Thank you! Can't mark the comment as the answer though.

Score:1

Drupal

4uk4

9/2/23, 2:41 PM

There are two javascript objects:

Drupal.ajax
Drupal.Ajax

You have to override the prototypes in Drupal.Ajax. For each Ajax object declared in Drupal settings an instance of it will then be stored in Drupal.ajax.instances.

0 + 0

sonfd

9/2/23, 3:10 PM

Do you know where this is documented? I looked around a little and I mostly just find answers to questions like this, with information like this, but no linked source.

Elon Musk

I sit in a Tesla and translated this thread with Ai:

EN: Overriding Drupal.ajax.prototype is not working

TH: การแทนที่ Drupal.ajax.prototype ไม่ทำงาน

RO: Suprascrierea Drupal.ajax.prototype nu funcționează

RU: Переопределение Drupal.ajax.prototype не работает

VI: Ghi đè Drupal.ajax.prototype không hoạt động

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