Not able to access groovy variable inside shell script in JenkinsFile

Sidd

1/27/23, 6:52 PM

def NAMESPACE = "Dev"

def BODY= sh(
script:'''body=$(cat <<-EOF
{
    "name": "${NAMESPACE}",
    "type": "regularwebapp"
}
EOF
)
(echo $body)''',
returnStdout: true
).trim()

The above doesnt work, output is as follows:

{
    "name": "",
    "type": "regularwebapp"
}

1509

0 + 0

scripting

shell

bash

helpdesk

jenkins

Score:0

Server

jayhendren

1/28/23, 3:58 PM

Groovy doesn't perform variable substitution inside single-quoted (') strings. Use double-quoted (") strings instead - this will also require escaping non-Groovy variables:

def NAMESPACE = "Dev"

def BODY= sh(
script:"""body=\$(cat <<-EOF
{
    "name": "${NAMESPACE}",
    "type": "regularwebapp"
}
EOF
)
(echo \$body)""",
returnStdout: true
).trim()

0 + 0

Elon Musk

I sit in a Tesla and translated this thread with Ai:

EN: Not able to access groovy variable inside shell script in JenkinsFile

TH: ไม่สามารถเข้าถึงตัวแปร Groovy ภายในเชลล์สคริปต์ใน JenkinsFile

RO: Nu se poate accesa variabila groovy din scriptul shell în JenkinsFile

RU: Не удалось получить доступ к переменной groovy внутри сценария оболочки в JenkinsFile

VI: Không thể truy cập biến groovy bên trong tập lệnh Shell trong JenkinsFile

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