How to use wget http status codes in an if else statement to take an action based on the status code

I'm writing a script that is downloading a bunch of files, I'm using wget to download the file and I want to echo back to the terminal custom status messages for each file based on 3 scenarios:

1. Files downloaded successfully (HTTP/1.1 200 OK)
2. Files did not change from the one locally (HTTP/1.1 304 Not Modified)
3. Anything else is a failed download

I'm able to get the status code and use awk to isolate just the status code number(200, 304, etc) I have the following to pull out the HTTP status:

#!/bin/bash
wget -NS http://ipv4.download.thinkbroadband.com/5MB.zip 2>&1 | grep "HTTP/" | awk '{print $2}'

if [ $? = 200 ]; then
echo "File downloaded
"
if [ $? = 304 ]; then
echo "File not modified from local copy"
else
    echo "Something went wrong"
    exit 1
fi

But this just prints the http status code back to the terminal, and always returns that last else statement.

laptop:~$ ./test.sh
304
Something went wrong

How do I send the output to run through an if else statement?

You are printing the HTTP status code to the standard output but your code compares a return code from wget, not a value printed to standard output. If there is no error then wget returns 0.

Your script needs to capture the output of the first command. There may be a more elegant approach, but the basic form:

wget_result="$(wget -NS http://ipv4.download.thinkbroadband.com/5MB.zip 2>&1|grep "HTTP/"|awk '{print $2}')"

if [ $wget_result = 200 ]; then
echo "File downloaded
"
if [ $wget_result = 304 ]; then
echo "File not modified from local copy"
else
    echo "Something went wrong"
    exit 1
fi