Running systemctl in Python script

Rayne

12/11/22, 3:47 AM

I'm trying to get the status of a few systemd services in Python, but I keep getting the error FileNotFoundError: [Errno 2] No such file or directory: 'systemctl show -p ActiveState --value abc'

I'm running Ubuntu 20.04, as the user user. The abc.service file is in /etc/systemd/system/, details below:

-rw-rw-r--  1 root root 1542 Aug  5 17:31  abc.service

The script is

import subprocess
status = subprocess.check_output("systemctl show -p ActiveState --value abc")
print(status)

However, if I run the systemctl command directly, I can get the status active. I've tried with sudo in the script, and I get the same error.

On a related note, I thought I would have to run the command using sudo eventually, but I'm actually running the command as part of my Airflow dag (i.e. not as a separate script where I can do sudo python3 myscript.py). Is there a way to do this?

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ajgringo619

12/11/22, 4:19 AM

I think this will help: https://stackoverflow.com/questions/2449250/any-way-to-assign-terminal-output-to-variable-with-python#2449301

Score:0

Ubuntu

Rayne

12/11/22, 6:19 AM

I was careless, and did not include shell=True in my subprocess. Once I added it, it runs successfully.

status = subprocess.check_output("systemctl show -p ActiveState --value abc", shell=True)

0 + 0

Elon Musk

I sit in a Tesla and translated this thread with Ai:

EN: Running systemctl in Python script

TH: เรียกใช้ systemctl ในสคริปต์ Python

RO: Rularea systemctl în scriptul Python

RU: Запуск systemctl в скрипте Python

VI: Chạy systemctl trong tập lệnh Python

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