How to append values to the list in shell script..?

us flag
cd /pg
file=`ls -l |awk '{print $9}'`
for i in $a
   echo $i
   a=`cat /pg/$i | head  -n  1 |awk '{print $8}' ` #output: first interation 15 & 2nd values 60
   #a1=`cat /pg/$i | head -n 2 |awk '{print $8}'`
echo $list

through this a=`ls -l |awk '{print $9}'` I'm getting two file and iterating through for loop and appending values to list() the list should contains "15","16" but list contains only one value is "15" Please help me to fix the same.

cn flag
Re-defining `$a` in the loop will not alter what `for` is iterating over: demo: `a="1 2 3 4 5"; for i in $a; do a="6 7 8 9"; echo $i; done`. If that is not your intention, pick a different variable name: using "a" for 2 different purposes is confusing.
tm flag

To access the whole array, use

echo "${list[@]}"

Using just $list is equivalent to ${list[0]}, i.e. it only shows the first element.

kr flag
# create list
# add hosts
hosts1+=( host1 )
hosts1+=( host2 )
hosts2+=( host3 )
hosts2+=( host4 )
# combine 2 lists
hosts1+=( ${hosts2[@]} )
# add some more
echo ${hosts1[@]}
hosts1+=( host5 )
hosts1+=( host6 )
echo ${hosts1[@]}

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