Purely parse the column from the bash command output

We need to extract the column from the command output. I have tried the methods using awk, and cut commands. Whereas we have the spaces in the 2nd column values due to which delimiter for space or other character does not parse the 2nd column output in a correct way. Do we have another method to get purely the second column of the output as mentioned above?

# cat info.txt
Vmid      Name                                                 File                                 
369    DO-NOT-DELL                          [datastore1] DO-NOT-DELL/DO-NOT-DELL.vmx                                
389    VMware vCenter Server                [datastore1] VMware vCenter Server/VMware vCenter Server.vmx            
390    Auth-vcenter-Don't delete            [datastore1] Auth-vcenter-Don't delete/Auth-vcenter-Don't delete.vmx    
393    VirtualMachine                       [datastore1] VirtualMachine/VirtualMachine.vmx                                            
9      Server 2005 for VM (dev team)        [datastore1] Server 2005 for VM (dev team)      

# cat info.txt | awk '{print $2}'
DO-NOT-DELL
VMware
Auth-vcenter-Don't
VirtualMachine
Server

As in the above output of a 2nd column we don't have the complete value as it in the original file.

It's possible to parse fixed-width columns with GNU awk:

The splitting of an input record into fixed-width fields is specified by assigning a string containing space-separated numbers to the built-in variable FIELDWIDTHS. Each number specifies the width of the field, including columns between fields. If you want to ignore the columns between fields, you can specify the width as a separate field that is subsequently ignored.

% awk -v FIELDWIDTHS="7 37 *" '{print $2}' foo
   Name                              
DO-NOT-DELL                          
VMware vCenter Server                
Auth-vcenter-Don't delete            
VirtualMachine                       
Server 2005 for VM (dev team)        

You can also use a regular expression as the field separator to split the text, so, e.g., using 3 or more spaces as the FS:

% awk -F ' {3,}' '{print $2}' foo
Name
DO-NOT-DELL
VMware vCenter Server
Auth-vcenter-Don't delete
VirtualMachine
Server 2005 for VM (dev team)

Convert spaces to tabs with non-default tab stop positions:

unexpand -t 7,44 info.txt | cut -f2

I also found a good approach from one of my friend to get the list of the virtual machines.

# cat info.txt | tr -s " " | cut -d "[" -f1 | cut -d " " -f2- | tail -n +2

                        
DO-NOT-DELL                          
VMware vCenter Server                
Auth-vcenter-Don't delete            
VirtualMachine                       
Server 2005 for VM (dev team)  

Multiple spaces between 'columns' can be used as awk field separator. This can be done by regex as [ ]{2,}

$ awk -F"[ ]{2,}" '{print $1}'
Vmid
369
389
390
393
9

$ awk -F"[ ]{2,}" '{print $2}'
Name
DO-NOT-DELL
VMware vCenter Server
Auth-vcenter-Don't delete
VirtualMachine
Server 2005 for VM (dev team)

$ awk -F"[ ]{2,}" '{print $3}'
File
[datastore1] DO-NOT-DELL/DO-NOT-DELL.vmx
[datastore1] VMware vCenter Server/VMware vCenter Server.vmx
[datastore1] Auth-vcenter-Don't delete/Auth-vcenter-Don't delete.vmx
[datastore1] VirtualMachine/VirtualMachine.vmx
[datastore1] Server 2005 for VM (dev team)