How to source and call a function within another function?

Morgan Zero

6/10/23, 9:04 AM

To my use case, I'm trying to accomplish calling on a function inside another function sourced from a different script. As you can see below, script1.sh is only called upon and wouldn't work if not called on function_main. Instead, I'm trying to call the functions within it from another script and I believe I'm missing something.

script1.sh:

function_main() {

echo "universe is "

  function_2nd() {

  echo "huge"

  }

  function_3rd() {

  echo "small"

  }

}

script2.sh:

read -p "What do you think about the universe? [B/S]" answer </dev/tty

case $answer in
b|B) source ~/script1.sh; function_main; function_2nd ;;
s|S) source ~/script1.sh; function_main; function_3rd ;;
*) ;;
esac

I'm grateful for any help!

0 + 0

bash

scripts

functions

choroba

6/10/23, 9:31 AM

What's the problem? The scripts work. If you remove `function_main` and declare the other functions in the top level, they will still work.

bac0n

6/10/23, 10:24 AM

this sounds like a [XY problem](https://xyproblem.info/)

Elon Musk

I sit in a Tesla and translated this thread with Ai:

EN: How to source and call a function within another function?

TH: จะจัดหาและเรียกใช้ฟังก์ชันภายในฟังก์ชันอื่นได้อย่างไร

RO: Cum să sursei și să apelezi o funcție în cadrul unei alte funcții?

RU: Как получить и вызвать функцию внутри другой функции?

VI: Làm cách nào để tìm nguồn và gọi một chức năng trong một chức năng khác?

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