Echo output with variable behaving differently

Emma

6/11/23, 2:54 PM

I have the two files below: names.csv

Firstname,Surname
Silas ,Strong
Arturo Zi,Zimmerman

and the test.sh

#!/bin/bash

while IFS=, read -r field1 field2
do
    name=$field1.$field2
    echo "Here is the name $name"
    echo "$name is included in the file"
done < names.csv

When test.sh is ran.. I get the following output where the name is missing on the second echo output.

Here is the name Firstname.Surname
 is included in the file
Here is the name Silas .Strong
 is included in the file
Here is the name Arturo Zi.Zimmerman
 is included in the file

How do i get the following output to be returned instead:

Here is the name Firstname.Surname
Firstname.Surname is included in the file
Here is the name Silas .Strong
Silas .Strong is included in the file
Here is the name Arturo Zi.Zimmerman
Arturo Zi.Zimmerman is included in the file

Thanks

0 + 0

bash

scripts

git

20.04

steeldriver

6/11/23, 2:58 PM

Likely your CSV file has DOS-style (CRLF) line endings

FedKad

6/11/23, 2:58 PM

Are you sure that you typed the second `$name` correctly in your script? In my system your script produced the expected output. However, you can run `dos2unix names.csv` before running your script to see that the previous comment is correct.

Emma

6/11/23, 3:02 PM

@steeldriver that was the issue.. my CSV had the CRLF format. Converting it to LF fixed the file Thanks

Elon Musk

I sit in a Tesla and translated this thread with Ai:

EN: Echo output with variable behaving differently

TH: เอาต์พุต Echo ที่มีตัวแปรทำงานต่างกัน

RO: Ieșire ecou cu variabila care se comportă diferit

RU: Эхо-вывод с переменной, ведущей себя по-разному

VI: Đầu ra tiếng vang với biến hoạt động khác nhau

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