How to pass an input as an argument in a bash script?

Amin Kaveh

11/7/23, 5:31 PM

I have a bash script that gets an input with the read command:

#!/bin/bash

read id

I can run the script $./my_script.sh and after that it wants me to enter the input (id). How can I enter the id as an argument to the script? I mean something like this:

$./my_script.sh id

100

1 + 0

bash

Score:1

Ubuntu

raj

11/7/23, 5:49 PM

Insert something like this in your script:

id=$1

$1 equals to the first command line argument passed to the script, $2 to the second one, etc.

Of course it would be wise to check first if the command line argument was provided at all. You can use something like this:

if [ -n "$1" ]; then
  id=$1
else
  read id
fi

The command (yes, it is a command) [ checks for a condition (an equivalent command is test). If the first argument is non-empty (-n), then the command id=$1 is executed; otherwise, read id is executed.

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