How to generate multiple files in sequence with data in sequence?

Muhammad Zahir Siddiqui

1/11/24, 11:52 PM

I have to create 50 files in sequence labelled r01.inp to r50.inp and in each file I need this text in sequence as well.

#!/bin/bash
abc2 r01.inp > r01.log

I used echo and touch to create the 50 files with same data but I still have to manually change r01.inp > r01.log to match the file name. Is there any way I can generate multiple files and the data inside it is also in a sequence i.e. r01.inp has abc2 r01.inp > r01.log while r02.inp has abc2 r02.inp > r02.log in it and so on.

1 + 0

command-line

bash

files

Score:2

Ubuntu

SHawarden

1/12/24, 12:23 AM

From google bash loop padded to StackOverflow How to zero pad a sequence of integers in bash so that all have the same width? I ended up with:

for i in $(seq -f "%02g" 1 50)
do
    echo "#!/bin/bash
abc2 r$i.inp > r$i.log" > r$i.inp
done

This will produce r01~r50.inp files and each file will contain the #!/bin/bash hashbang and the abc2 r##.inp > r##.log line as requested.

+ 1

steeldriver

1/12/24, 1:32 AM

You could also use `seq -w 1 50` or just use a bash *brace expansion* `{01..50}`

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