Apache2 Error Job for apache2.service failed because the control process exited with error code

I am trying to run an apache2 web server with linode and ubuntu. I got the following error

    Job for apache2.service failed because the control process exited with error code.
See "systemctl status apache2.service" and "journalctl -xeu apache2.service" for details.

After running

sudo service apache2 start

I ran the commands they offered and got:

systemctl status apache2.service

× apache2.service - The Apache HTTP Server
     Loaded: loaded (/lib/systemd/system/apache2.service; enabled; preset: enabled)
     Active: failed (Result: exit-code) since Fri 2023-04-28 12:59:56 UTC; 2min 13s ago
   Duration: 27min 6.692s
       Docs: https://httpd.apache.org/docs/2.4/
    Process: 6388 ExecStart=/usr/sbin/apachectl start (code=exited, status=1/FAILURE)
        CPU: 11ms

and

journalctl -xeu apache2.service
Hint: You are currently not seeing messages from other users and the system.
      Users in groups 'adm', 'systemd-journal' can see all messages.
      Pass -q to turn off this notice.
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-- No entries --

Does anyone know how to solve this? If you need any other information ask I just didn't want to overflow the question

First, read your error messages. Does id show that you're in one of the groups adm, or systemd-journal? Contact your system administrator or sudo adduser $USER systemd-journal, followed by logout/login, as groups are set up by login.

Alternatively you could use sudo;

sudo journalctl -xeu apache2.service

Second, your apache2 has been up for Duration: 27min 6.692s. Did you forget to stop the old apache2?

Third, is any other process listening on TCP Port 80? sudo lsof itcp:80. Clean that up. Port listening can't be shared.

Read man journalctl lsof sudo service.