How to find an expression with an unknown number of letters in the bash?

UnitedKingdom

8/19/24, 6:27 PM

How do I match a phrase with an unknown number of letters in the bash

I have these lines.

This is a line **s838e**
This is a line **s9e**

I want grep to return any line that contains a statement with such a syntax، but the number of numbers in the middle of the expression is unknown. How do I do that?

this expression: SUnknown_number_of_numbersE

Should I use another tool?

If you don't understand my question، I'm sorry، my English is so bad.

1 + 1

command-line

bash

Hannu

8/19/24, 7:33 PM

https://www.regular-expressions.info/

Score:0

Ubuntu

Arnaud Valmary

8/19/24, 8:43 PM

If you have your code like this:

phrase='This is a line **s838e**'

You could make a test like this:

if [[ "$phrase" =~ ^This\ is\ a\ line\ \*\*s[0-9]+e\*\*$ ]]; then
    echo "match"
else
    echo "not match"
fi

If french is your mother tongue, you could read this page: https://fr.wikibooks.org/wiki/Programmation_Bash/Regex

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