Why the variable value is not changing in the function?

ABSO

10/19/23, 1:24 AM

In the following function main_script, the variable DEFAULT_BACKUP_DIR is not working as intended because the value /home/user/BACKUP is not assigned to it which I do not know why, and when I try to update it in the if statement it also does not update

Note 1: This function is inside a Makefile that I use to run a Bach script file

Note 2: The variable DEFAULT_BACKUP_DIR is declared for the first time in this function and used within the scope of this function only.

define main_script
@ $(call src_dir_check,$1)
DEFAULT_BACKUP_DIR=/home/user/BACKUP
if [ -d $2 ]
then
    echo "Backup directory -$2- do exist"
    DEFAULT_BACKUP_DIR=$2
else 
    echo "ERROR! Backup directory -$2- does not exist!"
    echo "Switched to default directory -$(DEFAULT_BACKUP_DIR)-"
fi
$(call run_script,$1,$(DEFAULT_BACKUP_DIR),$3,$4)
endef

this is how I call it

.PHONY: run
run: display
    @ $(call main_script,$(SRC_DIR),$(BACKUP_DIR),$(TIME),$(MAX))

and I type the following in the terminal to run the Makefile

make run SRC_DIR=somedir BACKUP_DIR=somedir TIME=1 MAX=5

thanks in advance...

128

0 + 5

bash

makefile

Terrance

10/19/23, 1:42 AM

What type of script are you using this in? You tagged bash but bash doesn't use `define` at all to define any variables.

ABSO

10/19/23, 1:45 AM

@Terrance this function is inside a Makefile that I use to run a bash file

user68186

10/19/23, 1:49 AM

Which distro and version of Linux?

ABSO

10/19/23, 1:52 AM

@user68186 Ubuntu-20.04.3

Terrance

10/19/23, 1:56 AM

I have never created my own makefile, but from your code it just doesn't look quite right. I won't be much help because I am not seeing how you will be calling it. However, I do recommend that you look over the Makefile Tutorial https://makefiletutorial.com/

Elon Musk

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